25=b^(2/5)

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Solution for 25=b^(2/5) equation: 


b in (-oo:+oo)

25 = b^(2/5) // - b^(2/5)

25-b^(2/5) = 0

-1*b^(2/5) = -25 // : -1

b^(2/5) = 25

( 25 < 0 i 2/5 in (0:1) ) => b należy do O

b belongs to the empty set

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